Answer:
See below.
Step-by-step explanation:
Given :-
x² + bx + c = 0 if x₁ + x₂ = -b and x₁x₂ = c
Solving :-
a) x₁ = 1/2 and x₂ = -3/4
=> x² + -(1/2 + -3/4)x + 1/2(-3/4)
=> x² + -(-1/4)x + (-3/8)
=> x² + 1/4x - 3/8
=> 8x² + 2x - 3 = 0
b) x₁ = 1 + √5 and x₂ = 1 - √5
=> x² + -(1 + √5 + 1 - √5)x + (1 + √5)(1 - √5)
=> x² - 2x + 1 - 5
=> x² - 2x - 4 = 0
Answer:
−35.713332 ; 0.313332
Step-by-step explanation:
Given that:
Sample size, n1 = 11
Sample mean, x1 = 79
Standard deviation, s1 = 18.25
Sample size, n2 = 18
Sample mean, x2 = 96.70
Standard deviation, s2 = 20.25
df = n1 + n2 - 2 ; 11 + 18 - 2 = 27
Tcritical = T0.01, 27 = 2.473
S = sqrt[(s1²/n1) + (s2²/n2)]
S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]
S = 7.284
(μ1 - μ2) = (x1 - x2) ± Tcritical * S
(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284
(μ1 - μ2) = - 17.7 ± 18.013332
-17.7 - 18.013332 ; - 17.7 + 18.013332
−35.713332 ; 0.313332
2/7*3/8>3/8 because 2/7>1
Answer:
28,993
Step-by-step explanation:
Subtract 8,500 from 37,493
The answer is 28,993
Hope this helped :)
