Answer:
p = 
and q = 
Step-by-step explanation:
Given equations:
2p - 3q = 4 -----------(i)
3p + 2q = 9 ------------(ii)
Let's solve this equation simultaneously using the <em>elimination method</em>
(a) Multiply equation (i) by 3 and equation (ii) by 2 as follows;
[2p - 3q = 4] x 3
[3p + 2q = 9] x 2
6p - 9q = 12 -------------(iii)
6p + 4q = 18 -------------(iv)
(b) Next, subtract equation (iv) from equation (iii) as follows;
[6p - 9q = 12]
<u> - [6p + 4q = 18] </u>
<u> -13q = -6 </u> -----------------(v)
<u />
<u>(c)</u> Next, make q subject of the formula in equation (v)
q =
(d) Now substitute the value of q = into equation (i) as follows;
2p - 3() = 4
(e) Now, solve for p in d above
<em>Multiply through by 13;</em>
26p - 18 = 52
<em>Collect like terms</em>
26p = 52 + 18
26p = 70
<em>Divide both sides by 2</em>
13p = 35
p =
Therefore, p = and q =
square root of 30. Hope this helps
X = 3.5.....this is a vertical line that never crosses the y axis. It crosses the x axis at 3.5......so the x int is : (3.5,0)
y = -6.5...this is a horizontal line which never crosses the x axis. It crosses the y axis at -6.5....so the y int is (0,-6.5)
<h2>Hello!</h2>
The answer is:
C. Cosine is negative in Quadrant III
<h2>
Why?</h2>
Let's discard each given option in order to find the correct:
A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).
B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.
C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.
D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)
Have a nice day!
Answer:
Step-by-step explanation:
The angles labeled 4y - 8 and 79 + y are called vertical angles, and definition, vertical angles are congruent. That means algebraically, that
4y - 8 = 79 + y and
3y = 87 and
y = 29
