Given that the subway stations are 930 m apart, the train have to be accerelated for half the distance and then decerelated for the rest of the distance.
Recall that the distance travelled by an object with an initial velocity, u, for a period of time, t, at an accereration, a, is given by

But, we assume that the train accelerates from rest, thus

The maximum speed is attained at half the center of the distance between subway stations (i.e. at distance = 465 m).
Thus, maximum speed = distance / time = 465 / 23.12 = 20.11 m/s.
Answer: answer 40.
Step-by-step explanation:
Note : lets make x the missing denominator.
I would take the 4/5 and set it equals to 32/x
we then cross multiply
where it would be 4 * x = 32 * 5
it would then be 4x = 160
we would then divide 160 by 4
x = 160/ 4
and x would be 40
.... therefore the missing denominator is 40.
Answer:
Step-by-step explanation:
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Answer:
b
Step-by-step explanation:
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