So use the <span>Pythagorean Theorem. A^2 + B^2 = C^2 10^2 +12^2 = 15.6 hope this helps.
</span>
Answer:
3.66
Step-by-step explanation:
Answer:
The 99% confidence interval would be given by (0.286;0.562)
Step-by-step explanation:
Information given:
represent the families owned at least one DVD player
represent the total number of families
represent the estimated proportion of families owned at least one DVD player
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by
and
. And the critical value would be given by:
The confidence interval for the mean is given by the following formula:
If we replace the values obtained we got:
The 99% confidence interval would be given by (0.286;0.562)
The picture in the attached figure
we know that
RS=ST----------------> because is a square base
so
QS is the diagonal of the square base
applying the Pythagoras Theorem
QS²=RS²+ST²------> 6²+6²-----> QS²=72------> QS=√72----> QS=6√2 units
the answer isQS=6√2 units
<h3>
Answer: y = 5</h3>
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Explanation:
For any rectangle, the diagonals are always the same length. We can use congruent triangles to prove this.
This means AC = BD.
Also, the diagonals of a rectangle cut each other in half (bisect). This indicates the following two equations
We'll use that second equation along with BP = -2x+23 and DP = 3y-6 to form the equation -2x+23 = 3y-6. This will be used later.
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By the segment addition postulate, we know that
BP+DP = BD
(-2x+23)+(3y-6) = BD
BD = -2x+3y+17
Since the diagonals are equal, we also know that AC = -2x+3y+17
We are given that AC = 2x+4
Equating the two right hand sides leads to the equation 2x+4 = -2x+3y+17
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The conclusion of each the last two sections was the following two equations
- -2x+23 = 3y-6
- 2x+4 = -2x+3y+17
We have two equations and two unknowns. We have enough info to be able to find x and y.
Let's isolate 3y in the first equation
-2x+23 = 3y-6
3y-6 = -2x+23
3y = -2x+23+6
3y = -2x+29
Then we can plug this into the second equation
2x+4 = -2x+3y+17
2x+4 = -2x+(3y)+17
2x+4 = -2x+(-2x+29)+17 .... replace 3y with -2x+29
Now solve for x
2x+4 = -2x+(-2x+29)+17
2x+4 = -2x-2x+29+17
2x+4 = -4x+46
2x+4x = 46-4
6x = 42
x = 42/6
x = 7
We then use this to find y
3y = -2x+29
3y = -2(7)+29
3y = -14+29
3y = 15
y = 15/3
y = 5