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zaharov [31]
3 years ago
9

Find the missing factor 7s^2+25s+12=(s+3)()

Mathematics
1 answer:
Deffense [45]3 years ago
8 0
7s^2+25s+12=\\
7s^2+21s+4s+12=\\
7s(s+3)+4(s+3)=\\
(s+3)(7s+4)

It's 7s+4.
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3x−12≥15<br><br> 2x−5≤9<br><br> 5x+8≤53<br><br> 3x−5≥16
zalisa [80]

Answer:

Step-by-step explanation:

A) 3x−12≥15

3x ≥ 15 + 12

3x ≥ 27

or x≥ 9

B) 2x−5≤9

2x ≤ 9 +5

2x ≤ 14

or x ≤ 7

C) 5x+8≤53

5x ≤ 53 -8

5x ≤ 45

or x ≤ 9

D) 3x−5≥16

3x ≥ 16 + 5

3x ≥ 21

or x ≥ 7

Have a good day!

8 0
3 years ago
Which angles are vertical to each other ?
ankoles [38]

Answer:

5 and 7

Step-by-step explanation:

5 0
3 years ago
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Does this table represent a proportional relationship?<br><br> A) Yes<br> B) No
Nonamiya [84]

Answer:

a

Step-by-step explanation:

it is all doubles

7 0
3 years ago
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A factory makes 1200 shirts every 6 hours.the factory makes shirts for 9 hours a workday. what is the fewest number of workdays
Dominik [7]
1. Divide the target number of shirts, 12,600 by the company's rate of making the shirts. That is,
                                 number of hours = 12,600 shirts/ (1200 shirts/6 hours)
                                                               = 63 hours
2. Determine the number of workdays for them to complete the shirts by dividing 63 hours by 9 hours/workday. This will give us an answer of 7 workdays. 
8 0
3 years ago
Answering these questions
Rudiy27
1.\\ a)\ y=2x-3\ \ \ |subtract\ y\ from\ both\ sides\\\\\boxed{2x-y-3=0}\\\\b)\ y=\dfrac{1}{3}x-\dfrac{2}{5}\ \ \ |multiply\ both\ sides\ by\ 15\\\\15y=5x-3\cdot2\ \ \ |subtract\ 15y\ from\ both\ sides\\\\\boxed{5x-15y-6=0}


2.\\a)\ 5x-y+3=0\ \ \ |add\ y\ to\ both\ sides\\\\\boxed{y=5x+3}\\\\d)\ 7x+2y-3=0\ \ \ |subtract\ 7x\ from\ both\ sides\\\\2y-3=-7x\ \ \ |add\ 3\ to\ both\ sides\\\\2y=-7x+3\ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{y=-3.5x+1.5}


3.\\y=25x+100\ \ \ \ |subtract\ y\ from\ both\ sides\\\\\boxed{25x-y+100=0}
6 0
4 years ago
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