Answer:
18
Step-by-step explanation:
10-4+6(4-2)
10-4+6(2)
10-4+12
6+12
=18
To solve the inequality, you need to isolate/get x by itself:
171 > -6x Divide -6 on both sides [dividing/multiplying a negative number on
-28.5 < x [dividing/multiplying a negative number in an inequality causes the sign (<, >, ≤, ≥) to flip]
-28.5 < x [x is a number greater than -28.5]
So your graph should have an open circle at -28.5 (the first small line next to -28), and the arrow pointing to the right since x is greater than -28.5 (increasing) The 1st option is your answer
[use the o---> and put it at -28.5]
Answer:
Step-by-step explanation:
Write down the problem;
Simplify
Convert so that the fractions have a common denominator; multiply the numerator and denominator of both fractions such that the denominators are equal;
Add the fractions;
Convert to mixed number;
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0
As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81
Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2
So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2
A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.
3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.
So 2k^2 = 9 + 3k have two rational solutions (Option B).
Hope this Helps! :)
Answer:
The first one is the only one in simplest form.
