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strojnjashka [21]
2 years ago
12

A cone has a diameter of 6 cm and a height of 11.5 cm. Find the volume. Round your answer to the nearest 10th if necessary. Use

3.14 for pie.
Mathematics
1 answer:
uysha [10]2 years ago
5 0
V=πr^2h/3=π·3^2·11.5/3≈108.38495 or 108.40 rounded
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How many times larger is 7 x 106 than 3.5 x 10°?
pickupchik [31]

7 x 106 = 742 3.5 x 10 = 35 742-35=701.it is 701 time larger

6 0
3 years ago
Bobbie wants to make $2.00 using dollars ,half dollars , and quarters.how Many different ways can she make $2.00?
TEA [102]
70. Bobbie wants to make 2.00 dollars using dollars with the value of half dollars and quarters. Now, how many way he can do it? => half dollars = 0.5 => quarter dollars = 0.25 Possible ways: => 0.5 + 0.5 + 0.5 + 0.5 = 2 dollars (4 half dollars) => .25 + .25 + .25 +. 25 + .25 + .25 + .25 + .25 = 2 dollars (8 quarter dollars) => 0.5 + 0.5 + 0.25 + 0.25 + 0.25 + 0.25 = 2 dollars => 0.5 + 0.5 + 0.5 + 0.25 + 0.25 = 2 dollars => 0.5 + 0.25 + .25 + .25 + .25 + .25 + .25 = 2 dollars
3 0
3 years ago
Kamrynn is looking at her five quiz scores of 96 90 94 93 and 90. Determine the mean rounded to the nearest tenth median mode an
Romashka [77]

Answer:

Mean = 90, Median = 93, Mode = 90, Range = 6

Step-by-step explanation:

Mean:

96 + 90 + 94 + 93 + 90 = 463

463 ÷ 5 = 92.5

92.5 to nearest tenth = 90

Mean = 90

Median:

<em>90, 90</em>, <u>93</u>, <em>94 ,96</em>

Median = 93

Mode

<em>96, </em><u>90</u><em>, 94, 93, </em><u>90</u><em> </em>

Mode = 90

Range:

96 - 90 = 6

Range = 6

8 0
2 years ago
g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20
Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

X\sim N(\mu = 50, \sigma =6)

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0
2 years ago
5. Use each integer to describe a situation.<br> a) +5000:<br> b) -5:
gtnhenbr [62]

Answer:

A) +5000

Step-by-step explanation:

I'm not sure of my answer but

hope that help

7 0
2 years ago
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