100 POINTS!!! can someone help me please?? will give brainliest if correct!!
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The probability that a randomly selected x-value from the distribution will be in the interval:
- P(35 < x < 45) = 0.6827 and,
- P(30 < x < 40) = 0.47725
The probability of a normal distribution can be determined from the symmetrical curve between 1 to 100%.
From the information given:
- Mean = 40
- Standard deviation = 5
To determine the probability that a randomly selected x-value is in the given interval:
- P(35<x<45)
- P(30<x<40)
Using normal distribution table:
P(35 < x < 45) = 0.8414 - 0.1587
P(35 < x < 45) = 0.6827
Using normal distribution table:
P(30 < x < 40) = 0.5 - 0.02275
P(30 < x < 40) = 0.47725
Learn more about the probability of a normal distribution here:
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