Answer:
AB = ![\left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%266%5C%5C-6%263%265%5C%5C5%260%26-4%5Cend%7Barray%7D%5Cright%5D)
Each column of AB is written as a linear combination of columns of Matrix A in the explanation below.
Step-by-step explanation:
A = ![\left[\begin{array}{ccc}-2&2&1\\-3&1&1\\2&0&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%262%261%5C%5C-3%261%261%5C%5C2%260%26-1%5Cend%7Barray%7D%5Cright%5D)
B= ![\left[\begin{array}{ccc}2&-1&0\\1&2&1\\-1&-2&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-1%260%5C%5C1%262%261%5C%5C-1%26-2%264%5Cend%7Barray%7D%5Cright%5D)
We need to write each column of AB as a linear combination of the columns of A so we will multiply each column of A with each column element of B to get the column of AB. So,
AB Column 1 = 2 * ![\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%5C%5C-3%5C%5C2%5Cend%7Barray%7D%5Cright%5D)
+ 1 ![\left[\begin{array}{ccc}2\\1\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C1%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
+ (-1) ![\left[\begin{array}{ccc}1\\1\\-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5C%5C-1%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}-3\\-6\\5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%5C%5C-6%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
AB Column 2 = (-1) + 2 + (-2) = ![\left[\begin{array}{ccc}4\\3\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C3%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
AB Column 3 = (0) + (1) + 4 = ![\left[\begin{array}{ccc}6\\5\\-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%5C%5C5%5C%5C-4%5Cend%7Barray%7D%5Cright%5D)
Finally, we can combine all three columns of AB to form the 3x3 matrix AB.
AB =
Answer:
You can make 9 three Digit numbers
Step-by-step explanation:
The 9 three digit numbers are:
257
275
752
725
527
572
This can also be easily found out by multiplying the number of digits to the number of digits needed for the number, in this case, there are 3 digits, and the number must have 3 digits in them (without them repeating).
3 digits x 3 needed for the numbers = 9 three digit numbers
Answer:
y = 40 x = 80
Step-by-step explanation:
520 = 3.25x + 6.5y and x+y=120
x+y=120
x = 120-y
520 = 3.25(120-y)+6.5y
520 = 390-3.25y+6.5y
520 = 390+3.25y
130=3.25y
40 = y
x = 120-y
x = 120-(40)
x = 80
here's a graph
it cant be a negative number or zero
so now you are left with 0.5, 2 and 7.9
15.7 - 0.5 = 15.2 ( 15.2/2 = 7.6) this is possible
15.7 - 2 = 13.7 ( 13.7/2 = 6.85) this is possible
15.7 - 7.9 = 7.8 ( 7.8/2 = 3.9) (7.9/2 = 3.95) since the sides would be shorter than half the base this is not possible to form a triangle
so b can be either 0.5 or 2
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