Answer:
C
Step-by-step explanation:
C!
The probability that fewer than 4 of them are successful are 0.9527
<u>Explanation:</u>
Given:
number of trials, n = 6
p(successful) = 0.85
P(x >= 4) = ?
The problem can be solved using binomial probability formula.
P(x >= 4) = 1 - binomcdf(6,0.85,4) = 1 - 0.0473
= 0.9527
Therefore, the probability that fewer than 4 of them are successful are 0.9527
Answer:
y=2.50+175*(x-1)
$4727.50
Step-by-step explanation:
y=2.50+175*(x-1)
The first km costs 2.50 which is why you add it. You do x-1 because the 175 is charged for each additional km. So, if you traveled one km it would cost 2.50.
y=2.5+175*(28-1)
y=2.5+175*27
y=2.5+4725
y=$4727.50
Could you finish the problem and tell us what the problem is
Let 3<em>n</em> + 1 denote the "number" in question. The claim is that
(3<em>n</em> + 1)² = 3<em>m</em> + 1
for some integer <em>m</em>.
Now,
(3<em>n</em> + 1)² = (3<em>n</em>)² + 2 (3<em>n</em>) + 1²
… = 9<em>n</em>² + 6<em>n</em> + 1
… = 3<em>n</em> (3<em>n</em> + 2) + 1
… = 3<em>m</em> + 1
where we take <em>m</em> = <em>n</em> (3<em>n</em> + 2).
