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hodyreva [135]
3 years ago
9

Mark was watching a movie that was 124 minutes long. He fell asleep 75% of the way through. How many minutes of the movie did Ma

rk actually watch?
Mathematics
1 answer:
leva [86]3 years ago
3 0

Answer:

93 minutes

Step-by-step explanation:

Since 75 percent is just .75, multiply 124 by .75 to find out how much was watched. 124 * .75 = 93

Hopefully this helps- let me know if you have any questions

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People use water to​ cook, clean, and drink every day. An estimate of 19.4​% of the water used each day is for drinking. If a fa
Ronch [10]

Answer:

86.7 gallons

Step-by-step explanation:

I literally went decimal by decimal to find it. So theres no way it's wrong

4 0
3 years ago
If a bike is on sale for 45% off of the regular price. If the sale price is $299.75 what was the original price
7nadin3 [17]

Answer: It would of been $339.25

Step-by-step explanation: If you do the math  299 divided by 45 you  will get 40 so now add 40 to 299 you will get $339 minus 50 cents will be 25 so $339.25 would be the original price of the bike.

4 0
3 years ago
Read 2 more answers
Given that 1 inch = 2.54 cm, how many centimeters are there in 7 feet?
Zanzabum
The answer is 216.72 cm
8 0
3 years ago
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There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is
shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, n(P) = 6

Number of orange socks, n(O) = 4

Two socks are picked without replacement.

Now, total number of socks, n(T)=N(P)+n(O)=6+4=10

Probability of picking the first cap as purple cap is given as:

P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}

Now, probability that both the picked caps are purple is given by their probability product. This gives,

P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33

Therefore, the probability that he picked 2 purpled socks is 0.33

4 0
3 years ago
Game consoles: A poll surveyed 341 video gamers, and 89 of them said that they prefer playing games on a console, rather than a
Orlov [11]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the population proportion of gamers that prefer consoles is less than 28% as the manufacturer claims.

Of 341 surveyed players, 89 said that they prefer using a console.

The sample resulting sample proportion is p'= 89/341= 0.26

If the company claims is true then p<0.28, this will be the alternative hypothesis of the test.

H₀: p ≥ 0.28

H₁: p < 0.28

α: 0.05

To study the population proportion you have to use the approximation of the standard normal Z= \frac{p'-p}{\sqrt{\frac{p(1-p)}{n} } }≈N(0;1)

Z_{H_0}= \frac{0.26-0.28}{\sqrt{\frac{0.28*0.72}{341} } }= -0.82

This test is one-tailed left, i.e. that you'll reject the null hypothesis to small values of Z, and so is the p-value, you can obtain it looking under the standard normal distribution for the probability of obtaining at most -0.82:

P(Z≤-0.82)= 0.206

Using the p-value approach:

If p-value ≤ α, reject the null hypothesis

If p-value > α, don't reject the null hypothesis

The decision is to not reject the null hypothesis.

Then at a level of 5%, you can conclude that the population proportion of gamers that prefer playing on consoles is at least 28%.

I hope this helps!

4 0
4 years ago
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