1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hodyreva [135]
3 years ago
9

Mark was watching a movie that was 124 minutes long. He fell asleep 75% of the way through. How many minutes of the movie did Ma

rk actually watch?
Mathematics
1 answer:
leva [86]3 years ago
3 0

Answer:

93 minutes

Step-by-step explanation:

Since 75 percent is just .75, multiply 124 by .75 to find out how much was watched. 124 * .75 = 93

Hopefully this helps- let me know if you have any questions

You might be interested in
Plz helpppppppppppppppppppppppppppppppppppppppppppppppppppppp
BigorU [14]
D is the answer . . .
8 0
3 years ago
Read 2 more answers
The graph of f(x) = |x| is translated 6 units to the right and 2 units up to form a new function. Which statement about the rang
Novay_Z [31]

Answer:

Step-by-step explanation:

The answer is C, the range changes from (y | y > 0) to (y | y > 2)

sorry if i am wrong

7 0
3 years ago
Solve for x. Round all answers to the nearest tenth.<br> 9<br> X<br> 12
maria [59]

Step-by-step explanation:

x=54

use pyth then the other line = 15

then 15÷90 = 9÷x

then x = 54

8 0
3 years ago
Read 2 more answers
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
Find the value of x if 7,x and 11 are in A.p.​
krok68 [10]

Answer:

x = 9

Step-by-step explanation:

since the terms are in AP then there is a common difference between consecutive terms, that is

a₂ - a₁ = a₃ - a₂ ( substitute values )

x - 7 = 11 - x ( add x to both sides )

2x - 7 = 11 ( add 7 to both sides )

2x = 18 ( divide both sides by 2 )

x = 9

7 0
2 years ago
Read 2 more answers
Other questions:
  • COMBINING LIKE TERMS: Challenge 7 – 3ab + 2a + 6ab + 5 – 4a + 3a – ab​
    7·2 answers
  • Fraction as a decimal , use bar notation id necessary
    13·1 answer
  • What’s 6 I don’t get it need answers fast and 7 can anyone help?!
    15·1 answer
  • Helppppppppppppppppppppp
    5·1 answer
  • Solve this system with substitution:<br> 2x - 5y = 22<br> x + 5y = -4
    5·1 answer
  • 4y-5x=-8
    15·1 answer
  • What is the seventh term of an arithmetic sequence represented by the rule A(n) = 9+ (n 1)(-5)?
    9·1 answer
  • The lateral area of a cylinder is 100pi in^2. If its dimensions are reduced to one-fifth their original length, what would its n
    10·1 answer
  • A piece of paper is LaTeX: 8\frac{1}{2}8 1 2 inches wide. You tape 7 pieces of paper together to make a banner. How long is your
    11·1 answer
  • What is the result of subtracting a number greater than -3 but less than -2 from a number greater than 1 and less than 6
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!