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2 years ago

Which lines are perpendicular to the line y - 1 = 1/3 (x+2)? Check all that apply.

Mathematics

1 answer:

ioda2 years ago

7 0

Answer: Options 1, 3, 5

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals, so since the slope of the given line is 1/3, we need to find lines with a slope of -3.

Option 1 has a slope of -3.
Option 2 has a slope of 3.
Option 3 has a slope of -3.
Option 4 has a slope of 1/3.
If we subtract 3x from both sides, we get y=-3x+7, so option 5 has a slope of -3.

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A line goes through the points (4, 5) and (2, -6). Write the equation of the line in point-slope

Lerok [7]

Answer:

m (slope) = $\frac{11}{2}$

Step-by-step explanation:

point-slope form: m= $\frac{y2-y1}{x2-x1}$

(4, 5) (2, -6)

x1 y1 x2 y2

-------------------

$\frac{-6 - 5\\}{2 - 4}$ = m

-6 - 5 = -11

2 - 4 = -2

m = $\frac{11}{2}$

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2 years ago

Can someone teach me how to answer this? Thanks!

DaniilM [7]

Answer:

$\left( fg\right) \left( x\right) =2x^3\sqrt[3]{x}\\\\\left( \frac{f}{g} \right) \left( x\right) =\frac{2x^{3}}{\sqrt[3]{x} }$

Step-by-step explanation:

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1 year ago

A box contains 35 gems, of which 10 are real diamonds and 25 are fake diamonds. Gems are randomly taken out of the box, one at a

USPshnik [31]

Answer:

$Probability = 0.504$

Step-by-step explanation:

Given

$Gems= 35$

$Real = 10$

$Fake = 25$

Required

Determine the probability of selecting two fakes

The probability can be represented as thus: $P(Fake\ and\ Fake)$

Using the following probability formula, we have:

$P(Fake\ and\ Fake) = P(Fake) * P(Fake)$

Each probability is calculated by dividing number of fakes by total number of gems:

$P(Fake\ and\ Fake) = \frac{25}{35} * \frac{25-1}{35-1}$

The minus 1 (-1) represent the numbers of fake and total gems left after the first selection

$P(Fake\ and\ Fake) = \frac{25}{35} * \frac{24}{34}$

$P(Fake\ and\ Fake) = \frac{5}{7} * \frac{12}{17}$

$P(Fake\ and\ Fake) = \frac{60}{119}$

$P(Fake\ and\ Fake) = 0.504$

<em>Hence, the required probability is approximately 0.504</em>

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3 years ago

The graph of the relation T is shown below.

blsea [12.9K]

Answer:

The sets of the domain and the range of T are, respectively:

$Dom \{T\} =\{-3,0,3\}$

$Ran\{T\} = \{-4.-3,2,3\}$

Step-by-step explanation:

The values of the relation T that belongs to the domains correspond with the values on the x-axis and associated with the given points, whereas the range corresponds with the respective values of the y-axis. Let $T = \{(x,y)|(-3,3),(3,2),(0,-3),(3,-4)\}$

The sets of the domain and the range of T are, respectively:

$Dom \{T\} =\{-3,0,3\}$

$Ran\{T\} = \{-4.-3,2,3\}$

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2 years ago

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3 years ago