3 years ago

Given the information below, is (DB) ⃡ tangent to Circle A at point B? Justify with shown work.

Mathematics

1 answer:

Arisa [49]3 years ago

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Evaluate. −8/125−−−−√3 A. -4/25 B. −2/5 C. 4/25 D. 2/5

larisa [96]

The correct question is: evaluate

$\sqrt[3]{- \frac{8}{125} }$

The answer is: option B. -2 / 5

Explanation:

$\sqrt[3]{- \frac{8}{125} }=- \frac{ \sqrt[3]{8} }{ \sqrt[3]{125} } =- \frac{ \sqrt[3]{2^3} }{ \sqrt[3]{5^3} } =- \frac{2}{5}$

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3 years ago

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Natasha_Volkova [10]

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3 years ago

Which statement about y = x2 − x3 is true?

ad-work [718]

ANSWER

c.It is neither an odd nor an even function.

EXPLANATION

The given function is

$y = f(x) = {x}^{2} - {x}^{3}$

If this function is odd, then f(-a)=-f(a).

$f( - a) = {( - a)}^{2} - {( - a)}^{3}$

$f( - a) = {( a)}^{2} + {( a)}^{3}$

Now ,

$f( a) = {( a)}^{2} - {( a)}^{3}$

$- f( a) = - {( a)}^{2} + {( a)}^{3}$

Since

$f( - a) \ne - f(a)$

The function is not odd.

Also if the function is even, then

$f( a) = f( - a)$

Since

$f( a) \ne f( - a)$

the function is not even.

Hence the function is neither even nor odd.

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3 years ago

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