Dimension of one of the floors of one room that David wants to install tiles is 18feet long by 12 feet wide
Then
Area of the above room = 18 * 12 square feet
= 216 square feet
Dimension of the floor of the other room that David wants to install tiles is 24 feet long and 16 feet wide
Then
Area of the other room = 24 * 16 square feet
= 384 square feet
Then
The total square feet of the
rooms that David wants to install tiles = 216 + 384
= 600 square feet
Cost of the tile that covers 1 square feet = $5
Cost of the 4 tiles that cover 4 square feet = $17
Then
Area that can be covered with 4 square feet of tiles = 600/4 square feet
= 150 square feet
Minimum cost of covering
the two rooms that David wants to install tiles = 150 * 17 dollars
= 2550 dollars
So the minimum cost of installing the tiles on the two floors of David's two rooms is $2550. I hope the procedure is simple enough for you to understand.
Answer:
The mean = 17.54
Step-by-step explanation:
Form a table as below;
<u>Interval Frequency{f} Midpoint of frequency{x} fx </u>
1-7 19 4 76
8-10 14 9 126
11-15 15 13 195
16-20 20 18 360
21-35 10 28 280
36-50 13 43 559
Sum 91 1596
The mean of grouped data = Sum of { Interval Midpoint * Frequency } /Sum of frequency
The mean= 1596 / 91
The mean = 17.54
O2, or Oxygen, and C6H12O6, or glucose.
The answer is A. 5/12
Hope it helped!
It would be C because a coefficient is always with a variable and 6 is with a variable which makes it a coefficient
Hope this helps
Have a great day/night
