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Vlad [161]
3 years ago
9

WILL GIVE BRAINLIEST if you explain your answer!!

Mathematics
1 answer:
mr Goodwill [35]3 years ago
7 0

Answer:

x=-3

Step-by-step explanation:

You need to delete the root by ^2. First you need to leave it alone

\sqrt{x+7}-x=5\\\sqrt{x+7}=5-x\\(\sqrt{x+7} )^{2}=(5-x)^{2}    \\x+7=25+10x+x^2\\x-10x=25+x^2-7\\-9x=18+x^2\\-x^2-9x-18=0\\-1(x^2+9x+18)=0\\x^2+9x+18=\frac{0}{-1}\\x^2+9x+18=0\\(x+6)(x+3)=0\\x+6=0 ===> x=-6\\x+3=0 ===> x=-3\\Checking\\\sqrt{-6+7}-(-6)=5===>\sqrt{1}+6=7\neq5  \\\\\sqrt{-3+7}-(-3)=5===>\sqrt{4}+3=5=5\\\\So \\x=-3

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How do I get this answer?
Keith_Richards [23]

Answer:

Step-by-step explanation:

Several trig identities are involved in the proof of this. This is the order in which they are used.

  • cos(2x) = cos²(x) -sin²(x)
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<h3>Proof</h3>

Starting with the left side, we can transform it into the right side.

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4 0
1 year ago
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Answer:

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Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
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Step-by-step explanation:

8 0
2 years ago
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butalik [34]

Answer:

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Step-by-step explanation:

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Hope this helps! :)

8 0
2 years ago
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