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Luba_88 [7]
3 years ago
5

Ethan wants to put a fence around his vegetable garden. The garden is 30 feet wide and 15 feet long. If the total cost of the fe

nce is $810, what is the unit price of the fence per foot?
Mathematics
1 answer:
OverLord2011 [107]3 years ago
7 0
If the garden is square, then the perimeter would be 90. 15(2)+30(2)=90
810/90=9
So it would cost $9 per foot.
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Find a linear equation whose graph is the straight line with the given property.
jeka57 [31]

Answer:

y = 3/4x - 9/8

Then read explanation and see here with 2 coordinates would make

if 3/4 = -6 then 1 = -8

y = -6x + c

-6 / 3/4  + 9/8 / - 0.5  = -2.25

therefore c = -2.25

y = -6x - 2.25

y = -6x - 9/4  and again 9/4 can be found easily if round up fraction decimal to 225/100 and divide by 4

Step-by-step explanation:

C1)    (0.5 , -0.75)

C2)   ( 1. -3.75)

y = mx + c

-3.75 - - 0.75  /   1 - 0.5  = -3.75 + 0.75 / 0.5

= -3 / 0.5 = m

m = -6

y = -6x + c

then this works given just one coordinate to solve for 1 or 2 sets given points

y - y1 = mx+c

y - - 0.75 =  0.75 (x - x1)

y + 0.75 = 0.75 (x - 0.5)

y + 0.75 = 0.75x - 0.375

y = 0.75 - 0.75   =  0.75x( - 0.375 - 0.75)

y = 0.75x -1.125

y = 3/4x - 9/8    as common denominators of 1125/1000 is 9/8 as we divide by  125 into the fraction as we start at 250 and check its half just like when finding common denominators we 1/4 the lower number and see if we can find its half or its double etc with the other num er as first step for 3sf numbers.

5 0
3 years ago
Help! Quadrilateral ABCD is rotates 90 clockwise about the origin. What are the coordinates of quadrilateral A’B’C’D?
stepladder [879]

Answer:

its a i had this on my test

3 0
3 years ago
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What is the rate of change from 2012 to 2016?
Artyom0805 [142]

Answer:

D. 11.25 students per year

Step-by-step explanation:

8 0
2 years ago
A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions
salantis [7]

Dimensions are length 20 meter and width 14 meter

<em><u>Solution:</u></em>

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

<em><u>A rectangle has width that is 6 meters less than the length</u></em>

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

<em><u>The area of the rectangle is given by formula:</u></em>

Area = length \times width

<em><u>Substituting the values we get,</u></em>

Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0

<em><u>Solve the above equation by quadratic formula</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}

a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14

Since, length cannot be negative, ignore a = -14

<em><u>Thus solution of length is a = 20</u></em>

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

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151% find the decimal notation
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The answer to this should be 1.51
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