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Lana71 [14]
3 years ago
15

Jessie paid $43.75 for 5 movie tickets. Each ticket cost the same amount. What was the cost of each movie ticket in dollars and

cents?
Mathematics
2 answers:
N76 [4]3 years ago
5 0
If I’m not wrong each ticket was 8.75
Because 43.75 divided by 5= 8.75:)
Tanzania [10]3 years ago
3 0

Answer:

<u>$8.75</u>

Step-by-step explanation:

Divide $43.75 by 5 to get the cost of ONE movie ticket like so:

<u>$</u>43.75 / 5 <u>movie tickets</u> = $8.75 <u>per ticket</u>.

Therefore, ONE ticket costs $8.75.

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Each pack cost 3. he spent a total of 18 on gum. how many packs of gum did he buy.
TEA [102]

Answer:

So to figure that out you would take the money that he spend which was 18, each pack of gum cost 3, so to figure out the question you would simply divide 18 by 3 which would give you 6.

so how would you check that answer you could take 6 and multiple by the cost of each pack which would give you 18.

so answer is 6.

Step-by-step explanation:

18/3

=6

7 0
3 years ago
For a certain population of sea turtles, 18 percent are longer than 6.5 feet. A random sample of 90 sea turtles will be selected
nika2105 [10]

Answer:

The standard deviation of the sampling distribution of the sample proportion of sea turtles longer than 6.5 feet for samples of size 90 is of 0.0405

Step-by-step explanation:

Central Limit Theorem:

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

18 percent are longer than 6.5 feet.

This means that p = 0.18

A random sample of 90 sea turtles

This means that n = 90

What is the standard deviation of the sampling distribution of the sample proportion of sea turtles longer than 6.5 feet for samples of size 90

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.18*0.82}{90}} = 0.0405

The standard deviation of the sampling distribution of the sample proportion of sea turtles longer than 6.5 feet for samples of size 90 is of 0.0405

8 0
3 years ago
Team infinite dimensions canoed 15 3/4 miles in 3 hours. what was the average rate of speed in miles per hour?
pentagon [3]
Mi/h and mph. same thing I believe. I'm from Canada so I don't know what unit works but the ppl were going an average of 5.25miles per hour

5 0
3 years ago
Read 2 more answers
Hi Mariceo, when you submit this form, the owner will be able to see your name and email address.
Andreyy89
So you can see my email address? Haha sure...
6 0
3 years ago
Betty says that 90% of 180 days in 200 days. Is her answer reasonable
Gennadij [26K]

Answer:

yes

Step-by-step explanation:

cuz it is


8 0
4 years ago
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