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3 years ago

Please answer the question in the screen shot right

Mathematics

2 answers:

aleksandrvk [35]3 years ago

8 0

I can't access it can you tell me the question

nikdorinn [45]3 years ago

7 0

The shape has 7 sides so it will be:
-heptagon
-irregular polygon
-concave

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2 years ago

A triangle has sides of lengths 13, 21, and 24. is it a right triangle? explain

mel-nik [20]

<span>No, it doesn't. To find out if it's a right angled triangle, we use Pythagorean triple. It states that the square of the hypotenuse (the longest side) is equal to the sum of the squares of the opposite and adjacent sides. Obviously, the longest side, which is our hypotenuse is 24. So we want to find out whether the square of our hypotenuse is equal to the sum of the squares of the other two sides i. e 13 and 21. 24^ 2 = 576 ; 13^2 = 169 ; 21^2 = 441; So is 576 = 169 + 441. An emphatic No: hence the triangle isn't right angled since it doesn't satisfy pythagorean triple.. A^2 is not equal to B^2 + C^2 where a is the hypotenuse and b and c the opposite and adjacent sides.</span>

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2 years ago

15 points!!! GEOMETRY help please!!<br> Questions attached!

dolphi86 [110]

3. Look at the picture.

We have the right angle triangle. We know the sum of measures of angles in triangle is equal 180°. Therefore:

$x^o+90^o+43^o=180^o\\\\x^o+133^o=180^o\ \ \ |-133^o\\\\x^o=47^o$

$Answer:\ \boxed{47^o}$

4.
Look at the picture.

Use Pythagorean theorem:

$x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8$

$Used:\ (a+b)^2=a^2+2ab+b^2$

$Answer:\ \boxed{4.8\ units}$

5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}$

We have: $OP:\ y=-\dfrac{3}{2}x+b$

Now, we must find the slope of the line perpendicular to the line OP.
We know:

$k:y=m_1x+b;\ l:y=m_2x+c\\\\k\ \perp\ l\iff m_1m_2=-1$

therefore

$-\dfrac{3}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{3}\right)\\\\m_2=\dfrac{2}{3}$

So. We have the answer! :)

$Answer:\ \boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}}$

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2 years ago