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mr Goodwill [35]
3 years ago
7

Someone plz help me giving brainliest

Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0
I think the answer is 6
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The measure of an angle is seventy-one times the measure of a supplementary angle. What is the measure of each angle?
steposvetlana [31]

Let the smallest angle = x

Then the larger one = 71x

Supplementary angles are always equal to 180o

x + 71x = 180o Add the left side

72x = 180 Divide by 72

x = 180/72

x = 2.5

The smallest angle = 2.5 degrees

The largest angle = 2.5 * 71

The largest angle= 177.5 degrees.

3 0
3 years ago
Given that <br> y<br> = 8 cm and <br> θ<br> = 34°, work out <br> x<br> rounded to 1 DP.
morpeh [17]

Answer:

Step-by-step explanation:

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sin 34=x/8

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6 0
3 years ago
How do i solve for the inequality, p=3.4?​
Roman55 [17]

Answer:

Step-by-step explanation:

This is already solved, and this would not be considered a inequality since it has only a equal sign.

7 0
3 years ago
The parking garage charges $3 for the first hour of parking and $1.45 for each additional hour.
Alika [10]
I don't know what you are asking but my best guess is it will be
$4.46 in total
8 0
3 years ago
Read 2 more answers
Drag each tile to the correct box.
Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

\frac{f(b)-f(a)}{b-a}

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

f(a)=h(3)=4  

f(b)=h(5)=16

a=3

b=5

Substitute

\frac{16-4}{5-3}=6

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

f(a)=f(3)=10  

f(b)=f(6)=35

a=3

b=6

Substitute

\frac{35-10}{6-3}=8.33

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

g(x)=\frac{1}{5}(4)^x

f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}  

f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}

a=2

b=3

Substitute

\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0
3 years ago
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