Answer:
256x8y8256+2x8y8+56x3y7+28x7y2+126x5y4+x8+1048x7y+1932x6y2+2240x5y3+2310x4y4+2296x3y5+1932x2y6+1048xy7+y8+8x6y+56xy3+28x2y+8xy
Step-by-step explanation:
When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
cant factor so use quadratic formula
for
0=ax²+bx+c

so for
0=-16t²+25t+3
a=-16
b=25
c=3
so



it has to be a positive time
so it will hit the ground after

seconds
Cosine(angle) = adjacent leg/ hypotenuse
Cosine( angle ) = 18/20
Angle = arccos(18/20)
Angle = 26 degrees
The answer is A Ezra is right
Answer:
6
Step-by-step explanation: