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Verizon [17]
3 years ago
12

X + 4y = 13 x - y = 3 systems of equations I need help on a couple of these like ASAP

Mathematics
1 answer:
lara31 [8.8K]3 years ago
4 0
A.)
Slope:-1/4
Y intercept: (0,13/4)
X intercepts:(13,0)
B.)
X intercepts:(3,0)
Y intercepts:(0,-3)
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the width of a rectangle is 8 feet and the diagnal length of the rectangle is 13 feet which measurement is closest to the length
____ [38]

Answer:

Well the whole answer is 10.246950 smth smth but I don’t have the multiple choices so your gonna have to round yourself

Step-by-step explanation:

Okay so you have a weigh of 8 and a diagonal of 13.

If you look, theres a triangle there. One side has 8 and the diagonal that was cut forms a 13. So we have a leg and a hypotnuse. To find the other leg (length) just follow the Pythagorean theroum and solve for b or a.

Pythagorean theroum: a^2+b^2=c^2

Now subsitute c for 13 since its the hypotnuse and a or b as 8 but only one.

In this case I’m substituting a for 8.

8^2+b^2=13^2

Solve the squares

64+b^2= 169

Isolate the b

b^2=105

Now square root 105

√105 will give the answer above on a normal calculator but if you have to round, I don’t know what place but you can round.

7 0
3 years ago
Determine the x-intercept of the line whose equation is given:
Rudiy27

Answer:

Green

Step-by-step explanation:

cause blue and red make orange :)

8 0
3 years ago
Read 2 more answers
For each value of y, determine whether it is a solution to 12 = 2y +8.<br> Is it a solution
grin007 [14]

Answer: 2(0) + 8 does not equal 12, not a solution.

2(2) +8 = 12 yes it is a solution

2(-3) + 8 does not equal 12, not a solution

2(5) + 8 does not equal 12, not a solution.

Step-by-step explanation:

Looks like you need to plug in each y value given and multiplied by 2 and add 8

2(0) + 8 does not equal 12, not a solution.

2(2) +8 = 12 yes it is a solution

2(-3) + 8 does not equal 12, not a solution

2(5) + 8 does not equal 12, not a solution.

3 0
3 years ago
Water flows into a tank according to the rate F of t equals the quotient of 6 plus t and the quantity 1 plus t, and at the same
diamong [38]

Answer:

Step-by-step explanation:

The complete question is

Water flows into a tank according to the rate F(t)= (t+6)/(1+t), and at the same time empties out at the rate E(t)= (ln(t+2))/(t+1), with both F(t) and E(t) measured in gallons per minute. How much water, to the nearest galllon, is in the tank at time t=10 minutes.

Let C(t) be the amount of water in the tank at time t. We now that the rate of change of the tank is given by

\frac{dC}{dt}=[\tex]rate at which water flows in- rate at which water flows out. Then [tex]\frac{dC}{dt}=\frac{t+6}{t+1}-\frac{\ln(t+2)}{(t+1)}[\tex]so, the desired expression is obtained by integrating with respect to t. This leads us to [tex]C(t)  = \int \frac{t+1}{t+1}+ \frac{5}{t+1} - \frac{\ln(t+2)}{(t+1)} dt=t+ 5 \ln (|t+1|)-\int \frac{\ln(t+2)}{(t+1)} dt +C

Unfortunately, the integral \int \frac{\ln(t+2)}{(t+1)} dt cannot be expressed using fundamental functions. So, the problem cannot have an specific function (if you are willing to know the complete answer, the integral of this function uses the  polylogarithm function with n=2).

Since you want the exact amount of water at time, you need to give C a value, that is, you need to know an initial condition for the problem. This means, you need to know the amount of water in the tank at time 0

8 0
3 years ago
9.675,9.25,9.325,9.5 least to greatest
max2010maxim [7]
9.25, 9.325, 9.5, 9.675
8 0
3 years ago
Read 2 more answers
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