Option D. 2(n + 9) is the right answer
Step-by-step explanation:
The word problems are converted into mathematical problems to solve simply.
for the given problem
"two times the sum of a number and 9"
Let n be a number then
when there is and between two things they are performed first then next operation is performed so
the sum of a number and 9
Then
two times the sum of a number and 9
Hence,
Option D. 2(n + 9) is the right answer
Keywords: Mathematical notation
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Answer:
Step-by-step explanation:
y![f(x)^{-1} = inverse\\f(x)=y \\y = 1/(x^{3} \\Inverse: y=x ------------> x = 1/y^{3}\\y^{3} - \frac{1}{x} = 0\\y^{3} = \frac{1}{x}\\y = \sqrt[3]{\frac{1}{x}} \\y = \frac{\sqrt[3]{1} }{\sqrt[3]{x}} \\y = \frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=f%28x%29%5E%7B-1%7D%20%20%3D%20inverse%5C%5Cf%28x%29%3Dy%20%5C%5Cy%20%3D%201%2F%28x%5E%7B3%7D%20%5C%5CInverse%3A%20y%3Dx%20------------%3E%20x%20%3D%201%2Fy%5E%7B3%7D%5C%5Cy%5E%7B3%7D%20-%20%5Cfrac%7B1%7D%7Bx%7D%20%3D%200%5C%5Cy%5E%7B3%7D%20%3D%20%5Cfrac%7B1%7D%7Bx%7D%5C%5Cy%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7Bx%7D%7D%20%5C%5Cy%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B1%7D%20%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%20%5C%5Cy%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)
You are using the distributive property so you will multiply all the numbers in the parentheses by 5. So the end expression would be 30m+20n-15p
Answer:
x=4 cm
Step-by-step explanation:
x=smallest side
4x=hypotenuse
4√15=third side
use the Pythagorean Theorem
(4x)^2=x^2+(4√15)^2
16x^2=x^2+240
16x^2-x^2=240
15x^2=240
x^2=240/15
x^2=16
x=√16
x=4 cm is the smallest side
the hypotenuse is 16 cm
the third side is 4√15 cm
Answer:
At least 202.44 mm in the top 15%.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
How many yearly mm of rainfall would there be in the top 15%?
At least X mm.
X is the 100-15 = 85th percentile, which is X when Z has a pvalue of 0.85. So X when Z = 1.037.
At least 202.44 mm in the top 15%.
