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DedPeter [7]
3 years ago
5

Please help it’s due in 20 mins would it be A B C or D

Mathematics
2 answers:
KIM [24]3 years ago
8 0
Option C is correct

x < 1
yKpoI14uk [10]3 years ago
4 0

Answer:

C ) x < 1

Step-by-step explanation:

The open circle on a number line means: less than or greater than. The arrow is pointing to the left, towards the negatives, so x would be less than 1.

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What are two numbers that are 4 away from zero on a number line?
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Answer:

4 and -4

Step-by-step explanation:

Because 4 to the left of 0 is negative and 4 to the right is positive

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Which table represents a function?
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Answer:

table 1

Step-by-step explanation:

table one, because you have different value of x (inputs) with no repetition for the same value

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Write 0.57 as a fraction in simplest form.<br> 0.57 <br> Lower number fraction
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Answer:

14.25/25

Step-by-step explanation:

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On a map, 1.5 centimeters = 75 kilometers. How far apart are two cities that are 12 centimeters apart on the map?
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-x^2+50=25 solve the equation
Andru [333]

Answer:

Two solutions were found :

x = 5

x = -5

Step-by-step explanation:

Step  1  :

Trying to factor as a Difference of Squares :

1.1      Factoring:  25-x2

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  25  is the square of  5

Check :  x2  is the square of  x1

Factorization is :       (5 + x)  •  (5 - x)

Equation at the end of step  1  :

 (x + 5) • (5 - x)  = 0

Step  2  :

Theory - Roots of a product :

2.1    A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

2.2      Solve  :    x+5 = 0

Subtract  5  from both sides of the equation :

                     x = -5

Solving a Single Variable Equation :

2.3      Solve  :    -x+5 = 0

Subtract  5  from both sides of the equation :

                     -x = -5

Multiply both sides of the equation by (-1) :  x = 5

Two solutions were found :

x = 5

x = -5

Processing ends successfully

plz mark me as brainliest :)

6 0
3 years ago
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