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Sunny_sXe [5.5K]
3 years ago
13

There u go you're all set and there's more to come thank you so much

Mathematics
1 answer:
tatiyna3 years ago
3 0
I believe it is 50-12p =26 because she start off with 50 than she subtracts the cost for all 12 rides to get the remainder of 26.

You might be interested in
X + 2 = 5x solve for x.
ivanzaharov [21]

Answer:

x = 1/2 or 0.5

Step-by-step explanation:

Subtract 2 from both sides of the equation

x + 2 - 2 = 5x -2

Simplify

x = 5x -2

Subtract 5x from both sides of the equation

x = 5x -2

x - 5x = 5x - 2 - 5x

Solution

x = 1/2

Hope this helps!! :))

https://brainly.com/

8 0
2 years ago
Read 2 more answers
What is he total coast to print exactly 15 copies?
artcher [175]

You would start by finding out how much 10 and 20 cost per copy

10: 40-25 = 15/10 = $1.50 dollars per copy

20 (This is for checking your math, not required): 55-25 = 30/20 = $1.50 dollars per copy

So, to find 15 copies you would use this formula: 25 + 1.5x

25 + 1.5(15)

25 + 22.5

$47.50 for 15 copies

Now for the second question:

160 - 25 = 135/1.5 = 90 copies

90 copies for $160

8 0
3 years ago
Is 137 degrees the same as c degrees? If not, someone explain please.
aev [14]
Yes it is. Also, a= 43 & b=43
4 0
3 years ago
If 2x - 5 = 11. what is 3x?
Anna71 [15]

Answer:

24

Step-by-step explanation:

add 5 to both sides to get 2x=16

divide both sides by 2

x=8

3(8)=24

4 0
3 years ago
Read 2 more answers
It has been observed that the average number of traffic accidents requiring medical assistance on the Hollywood Freeway between
Vesna [10]

Answer:

0.184

Step-by-step explanation:

As the statistician consultant, I would have to calculate the chance of having 2 ambulances on the freeway at this hours and relay the message to the dispatcher.

Probability of having the need for 2 ambulances.

We will have a poisson distribution:

Lambda = 1

P(x=2) = e^-2*1/2!

= 2.71828^-1/2

= 0.368/2

= 0.184

I would tell the dispatch rider that the possibility that 2 ambulances would be required is 0.184.

Thank you

7 0
3 years ago
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