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Marianna [84]
3 years ago
5

A spinner has 6 numbers on it, from 1-6, all with equally spaced area. Find the probability of spinning a

Mathematics
1 answer:
shutvik [7]3 years ago
6 0

Answer:

first option 1/2

Step-by-step explanation:

2,3,5 are the prime numbers from that set

each individual number has a 1 in 6 chance of landing on it and we have 3 so...

3 of 6 possibilities would be prime numbers. Simplify to...

1 in 2

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V=π x r2 x h/3 that’s the formula
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What is the common ratio for this geometric sequence?<br> 27, 9, 3, 1, ...
Lesechka [4]

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27:9 3:1.................

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3 years ago
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A manufacturing company wants to use a sample to estimate the proportion of defective tennis balls that are produced by a machin
Kitty [74]

Answer:

The least number of tennis balls needed for the sample is 1849.

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population proportion is:

 CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error for this interval is:

 MOE= z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

Assume that the proportion of all defective tennis balls is <em>p</em> = 0.50.

The information provided is:

MOE = 0.03  

Confidence level = 99%

<em>α</em> = 1%

Compute the critical value of <em>z</em> for <em>α</em> = 1% as follows:

 z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58

*Use a <em>z</em>-table.

Compute the sample size required as follows:

 MOE= z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

       n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)} }{MOE}]^{2}

          =[\frac{2.58\times \sqrt{0.50(1-0.50)} }{0.03}]^{2}\\\\=1849    

Thus, the least number of tennis balls needed for the sample is 1849.

8 0
3 years ago
Solve the equation x/3 -5- y for x.​
Tomtit [17]

Answer:

Well first of all, that isn't an equation, I wil however interpret it as best as I can.

x = 25 + 5y

Step-by-step explanation:

x/5 - 5 - y for x, so, x/5 - 5 - y = 0.

Add 5 and y to both sides.x/5 = 5+ y, multiple both sides by 5.

x = 25 + 5y

5 0
3 years ago
A prior study estimated as 34%. The analysts would like to conduct a second study on the same topic with a margin of error, E, o
Volgvan
The minimum sample size required for a test with a confidence interval of 100(1 - \alpha )% with a z-score of z_{ \alpha /2} and margin of error of E and a population proportion of p is given by:

n= \frac{p(1-p)z_{ \alpha /2}^2 \alpha }{E^2}

Given p = 34% = 0.34, E = 0.027, z_{ \alpha /2}=1.645

Therefore, 

n= \frac{0.34(1-0.34)(1.645)^2}{0.027^2}  \\  \\ = \frac{0.34(0.66)(2.706025)}{0.000729} = \frac{0.60723201}{0.000729}  \\  \\ =832.97=833 
4 0
3 years ago
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