Given : A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week . and graph
To Find : Maximum profit , breakeven point , profit interval
Solution:
The maximum profit the florist will earn from selling celebration bouquets is $ 675
peak of y from Graph
The florist will break-even after Selling 20 one-dollar decreases.
at breakeven
Break even is the point where the profit p(x) becomes 0
The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is (0 ,20).
after 20 , P(x) is - ve
The first one 6 second 8 but it’s funny
The correct statement regarding the function plotted in the graph is:
C) The maximum value of the quadratic function occurs at y = 4.
<h3>What is the rate of change of the linear function?</h3>
When x = 0, y = -7, and when x = -5, y = 8, hence the rate of change(change in y divided by change in x) is given by:
R = [8 - (-7)]/-5 - 0 = 15/-5 = -3
<h3>What is the maximum value of the quadratic function?</h3>
It is concave down, hence it has only a maximum value at y = 4 and not a minimum value, hence option C is correct.
More can be learned about functions at brainly.com/question/25537936
IGH because the angles line up
Answer:
The y-intercept should be 346,904. This is the population for the first (first/last( known year of data. The year 2000 acts as 0 on the graph of the exponential function.
Step-by-step explanation:
I just did it on my homework and it said that my answer is right
