-4 _> 4(6y-12)-2y
first distribute/ simplify the equation
-4 _> 24y-48-2y
then combine like terms
-4 _> 22y-48
solve for y
-4 _> 22y-48
44 _> 22y
2 _> y
so the answer is y <_ 2 ( y is less than or equal to 2)
Hello! For ease of calculations, we can identify the time it took for the weight to bounce back to the other direction, then the other, and then back to its original position by looking at the time it took for the weight to change from 0 to 25 to 0 to -25 then back to 0. This is one whole cycle of the weight.
By the time the weight first reached zero, 1.5 seconds has passed. By the third time it got to zero again, 7.5 seconds has passed. Therefore, one whole cycle of the weight is 7.5-1.5 = 6.0 seconds.
ANSWER: One whole cycle of the weight took 6 seconds.
Answer:
Hey there!
These would also be acute angles.
Let me know if this helps :)
Answer:
5
Step-by-step explanation:
