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lyudmila [28]
3 years ago
13

I’m having a bit of trouble please help me

Mathematics
1 answer:
Vanyuwa [196]3 years ago
8 0

Answer:

wouldnt it be -4 -4??since it going from 4 to 4 maybe

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Please answer question with work ♥️
vova2212 [387]

Answer:

r=201

d = 77 1/2

Step-by-step explanation:

6) First multiply left and right by 16, to get rid of the fraction:

r - 25 = 11*16

Now add 25 left and right:

r = 11*16 + 25 = 201


7) Add 5 left and right

2/5 d = 31

multiply by 5/2

d = 31 * 5/2 = 77 1/2

3 0
3 years ago
Question is below help needed
RoseWind [281]

The common ratio of both the formulas is 3 and 2. The first formula is explicit and the second is the recursive formula.

<h3>What is the recursive rule?</h3>

A rule is defined such that its definition includes itself.

1.

The given sequence is

-2, -6, -18, -54

Common ratio ;

r = -6 / -2 = 3

a _ n =-2 (3) ^{n-1}

This given formula is the explicit formula.

2.

The given sequence is

4, 8, 16, 32

Common ratio ;

r = 8 / 4 = 2

a_n = a_{n-1}.2\\\\a _1 = 4

This given formula is the recursive formula.

Learn more about the recursive rule and explicit rules here:

brainly.com/question/12620593

#SPJ1

5 0
2 years ago
What is the area of the triangle that is 30 m base in the height of 12 m in a straight line of 13
Reika [66]

Answer:

60

Step-by-step explanation:

3 0
3 years ago
Given the system of linear equations.
Karo-lina-s [1.5K]

Part A:


x + y = 9

4x + y = 6


To solve this system using substitution, begin by isolating either x or y in the first equation. I'll isolate x.


x + y = 9

x = 9 - y


Substitute this expression (9 - y) into the second equation for x and solve.


4x + y = 6

4(9 - y) + y = 6

36 - 4y + y = 6

36 - 3y = 6

-3y = -30

y = 10


To find x, substitute 10 for y into either of the original equations.


x + y = 9

x + 10 = 9

x = -1


Finally, check all work by substituting the x- and y-values into each original equation.


x + y = 9   -->   -1 + 10 = 9   -->   9 = 9   -->   True

4x + y = 6   -->   4(-1) + 10 = 6   -->   -4 + 10 = 6   -->   6 = 6   -->   True


The answer for Part A is x = -1 and y = 10; (-1, 10).


Part B:


For graphing, it's easier to get the equations into slope-intercept form. Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. To get our equations into slope-intercept form, we must simply isolate y.


x + y = 9

y = 9 - x

y = -x + 9


4x + y = 6

y = 6 - 4x

y = -4x + 6


Now that we have our slope-intercept equations, we can easily graph them, since their slopes and y-intercepts are readily visible.



Let's start with the y-intercepts. They are (0, 9) and (0, 6). You can plot those points on the graph.


Now, the slopes. The slope of the first line is -1, this means it declines. To plot this, start where you plotted the y-intercept, count one unit down, and then one unit to the right, and plot that point. Continue doing that and connect the dots, and you will have plotted the first line. The slope of the second line is -4, so it also declines. For this line, count four units down, and then one to the right and plot that point. Likewise, continue this and connect the coordinates, and you will have your line. (See attachment for graph.)


The lines do indeed intersect at (-1, 10); our answer is verified by graphing.

5 0
3 years ago
What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
telo118 [61]

Answer:

f(x)=-\frac{1}{8}(x-3)^2+3

Step-by-step explanation:

We want to find the equation of the parabola with a focus of (3,1) and directrix y=5.

Considering the directrix, the quadratic graph must open downwards.


The equation of this parabola is given by the formula,

(x-h)^2=4p(y-k), where (h,k) is the vertex of the parabola.


The axis of this parabola meets the directrix at (3,5).

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,


h=\frac{3+3}{2}=3 and k=\frac{5+1}{2}=3.


The equation of the parabola now becomes,


(x-3)^2=4p(y-3).


Also |p| is the distance between the vertex and the directrix.


|p|=2


This implies that p=-2\:or\:2.


Since the parabola turns downwards,


p=-2.



Our equation now becomes,


(x-3)^2=4(-2)(y-3).


(x-3)^2=-8(y-3).


We make y the subject to get,

y=-\frac{1}{8}(x-3)^2+3).


This is the same as

f(x)=-\frac{1}{8}(x-3)^2+3).









4 0
3 years ago
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