All categories

3 years ago

Help me please show ur work

Mathematics

1 answer:

Lisa [10]3 years ago

5 0

Let the length of the patio is x and width is 3/4x
So according to the equation x.3/4x = 432
x^2. 3/4 =432
x^2 =432 times 4/3
x^2 =1728/3 =576
x= 24

The length is 24 ft

You might be interested in

Juan lives 100 miles away from Bill.What is Juan's average speed if he reaches Bill's home in 50 seconds?

motikmotik

50 because 100 if you break it then its 50

4 0

4 years ago

Read 2 more answers

Solve using elimination.<br> 6x + 8y = -4<br> -6x - 10y = 14

jok3333 [9.3K]

Answer:

x = 6, y = -5.

Step-by-step explanation:

6x + 8y = -4

-6x - 10y = 14 Adding will eliminate the terms in x:

0 - 2y = 10

y = 10/-2 = -5,

Plug this into the second equation:

-6x - 10(-5) = 14

-6x = 14 - 50 = -36

x = -36/-6

x = 6.

3 0

3 years ago

Read 2 more answers

If sin theta = 2/3 and sex theta < 0 , find cos theta and tan theta

FromTheMoon [43]

Answer:

$\displaystyle cos\theta=-\frac{\sqrt{5}}{3}$

$\displaystyle tan\theta=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

<u>Trigonometric Formulas</u>

To solve this problem, we must recall some basic relations and concepts.

The main trigonometric identity relates the sine to the cosine:

$sin^2\theta+cos^2\theta=1$

The tangent can be found by

$\displaystyle tan\theta=\frac{sin\theta}{cos\theta}$

The cosine and the secant are related by

$\displaystyle cos\theta=\frac{1}{sec\theta}$

They both have the same sign.

The sine is positive in the first and second quadrants, the cosine is positive in the first and fourth quadrants.

The sine is negative in the third and fourth quadrants, the cosine is negative in the second and third quadrants.

We are given

$\displaystyle sin\theta=\frac{2}{3}$

Find the cosine by solving

$sin^2\theta+cos^2\theta=1$

$\displaystyle \left(\frac{2}{3}\right)^2+cos^2\theta=1$

$\displaystyle cos^2\theta=1-\left(\frac{2}{3}\right)^2=1-\frac{4}{9}=\frac{5}{9}$

$\displaystyle cos\theta=\sqrt{\frac{5}{9}}=-\frac{\sqrt{5}}{3}$

$\boxed{\displaystyle cos\theta=-\frac{\sqrt{5}}{3}}$

We have placed the negative sign because we know the secant ('sex') is negative and they both have the same sign.

Now compute the tangent

$\displaystyle tan\theta=\frac{sin\theta}{cos\theta}=\frac{\frac{2}{3}}{-\frac{\sqrt{5}}{3}}=-\frac{2}{\sqrt{5}}$

Rationalizing

$\displaystyle tan\theta=-\frac{2}{\sqrt{5}}=-\frac{2\sqrt{5}}{5}$

$\boxed{\displaystyle tan\theta=-\frac{2\sqrt{5}}{5}}$

5 0

4 years ago

What is the square root of 6 8 21?

enyata [817]

$\sqrt{6821}$ =82.59

8 0

3 years ago

If 12 oranges cost $4.20, what is the unit price?

Tcecarenko [31]

Answer:

50.4

Step-by-step explanation:

4.20x12

4 0

3 years ago

Read 2 more answers