1. Let a: rolling an even number, b: rolling an odd prime number
2. a={2, 4, 6, 8, 10, 12, 14, 16}, b={3, 5, 7, 11, 13}
3. So n(a)=8, n(b)=5 , n(Sample Space)=n(S)=16
4. Since a and b are mutually exclusive events, that means they have no common elements, P(a or b)=P(a)+P(b)=
Well, I believe you can set up a proportion for this. So:
d/c = d/c or 8/9 = x/6
*cross multiply*
9x = 48
*divide both sides by 9 to get x by itself*
x = 5 1/3
Make a ratio, then cross multiply.
4/30=x/48
30x=4x48
30x=192
x=6.4
Answer:
The number of tickets sold to the public was 375
Step-by-step explanation:
<u><em>The complete question is</em></u>
At a charity basketball game, 450 tickets were sold to students at a school. The remaining x tickets were sold to the public. The students paid $15 and public $25. When all the tickets were sold, $10,500 was collected. How many tickets were sold to the public?
Let
x ----> number of tickets sold to the students
y ----> number of tickets sold to the public
we know that
----> equation A
----> equation B
Solve the system by graphing
The solution is the intersection point both graphs
using a graphing tool
The solution is the point (75,375)
see the attached figure
therefore
The number of tickets sold to the public was 375
Answer:
The answer should be B. 86.7
