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Aneli [31]
3 years ago
11

You have a square(40 inches by 24 inches) and reduce it to create the smaller box of 10 inches by 6 inches. What is the scale fa

ctor?
Mathematics
1 answer:
Gnoma [55]3 years ago
3 0

Answer:

4 inches

Step-by-step explanation:

40/24=10/6

40/10=4

24/6=4

(40/24)/(4/4)=10/6

(10/6)(4/4)=10/24

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IR = V (solve for R) *
VashaNatasha [74]

Answer:

R = \frac{V}{I}

Step-by-step explanation:

IR = V ( isolate R by dividing both sides by I )

R = \frac{V}{I}

6 0
2 years ago
Solve for x t=1/2(1/x-1/y)
Ilya [14]

Answer:

Step-by-step explanation:

671518 jnaja(a iuyquq uhh 71718(2961881

8 0
3 years ago
Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val
Cloud [144]

Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

A(t) = Pe^{rt}

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

$330 in an account in the year 1999

This means that P = 330

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

A(t) = Pe^{rt}

590 = 330e^{8r}

e^{8r} = \frac{590}{330}

e^{8r} = 1.79

Applying ln to both sides:

\ln{e^{8r}} = \ln{1.79}

8r = \ln{1.79}

r = \frac{\ln{1.79}}{8}

r = 0.0726

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

A(t) = 330e^{0.0726t}

A(10) = 330e^{0.0726*10} = 682

The value of the account in the year 2009 will be $682.

4 0
3 years ago
Solve, please so it fast
jek_recluse [69]
I Think the answer is 17
6 0
3 years ago
How do I solve this?
Aleksandr-060686 [28]
First you have to set up your equation. 5x+80 and x+15. 
8 0
3 years ago
Read 2 more answers
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