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vladimir1956 [14]
3 years ago
5

Please help asap calculate the slope of the line through the points (6,-8) and (3,-4).

Mathematics
2 answers:
sammy [17]3 years ago
5 0

Answer: y = -4/3x + 0. Yes, that point lies on the line

Step-by-step explanation:

Use this equation, Δy/Δx and this one, y = mx + b. Or, change in the y value divided by the change in the x value.

-4 + 8 = 4

3 - 6 = -3

The slope, m, is -4/3. Now solve for b by plugging in the slope.

-4 = \frac{-4}3 (3) + b. B is equal to 0

To see if that point lies on the function, plug it in the equation and see if it is true. Multiply -4 x -3 to get 12, divide by 3 to get 4, then add 0. The equation says that 4 = 4, which is infact true

Reptile [31]3 years ago
3 0

Answer:

<u> y=-4x/3</u>

<u> the point (-3,4) is on the line y= -4x/3</u>

Step-by-step explanation:

the points (6,-8) and (3,-4)

<em><u>a) (y- y1)/(y2- y1)=(x- x1)/(x2- x1) </u></em>

(y+8)/(-4+8)=(x-6)/(3-6)

(y+8)/4=(x-6)/(-3)

-3y-24=4x-24

<u>So, y=-4x/3</u>

b) (-3; 4)

4= -4*(-3)/3

4=4 it is true,

<u> the point (-3,4) is on the line y= -4x/3</u>

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