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Lilit [14]
3 years ago
13

1. If y varies inversely as x and x = 2 when y = 8, find x when y= 5.

Mathematics
1 answer:
Hitman42 [59]3 years ago
3 0

Answer:

16/5

Step-by-step explanation:

Since y varies inversely as x,  then xy = k  

                                                          2(8) = 16 = k

Therefore, xy = 16

Now,  5x = 16

x = 16/5

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Among two supplementary angles, the measure of the larger angle is 44°
zhuklara [117]

Answer:

68° and 112°

Step-by-step explanation:

Supplementary angles sum to 180°

let the smaller angle be x then the larger angle is x + 44 , then

x + x + 44 = 180 , that is

2x + 44 = 180 ( subtract 44 from both sides )

2x = 136 ( divide both sides by 2 )

x = 68

Smaller angle = 68° and

larger angle = x + 44 = 68 + 44 = 112°

6 0
3 years ago
A cylinder has a height of 7 inches and a radius of 14 inches. What is its volume? Use a
icang [17]

Answer: Volume is 4308.1 in³

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3 0
2 years ago
What is the slope of a line perpendicular to the line y= - 2/3x + 1
sesenic [268]
3/2 since perpendicular lines have opposite reciprocal slopes
7 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Anit [1.1K]
Well the area of a trapezoid is defined by the following formula:
A = \frac{1}{2}(b_{1} + b_{2})h where b₁ and b₂ are the bases of the trapezoid and h is the height of the trapezoid.

Let's plug in what we know into this formula:
h = 7  the perpendicular distance between the two bases
b₁ = 15  the shorter parallel side
b₂ = 25  the longer parallel side made up of 4 + 15 + 6
so, A = \frac{1}{2} (15+25)(7)=140

This is in square units of measure of course, so 140 in² 
8 0
3 years ago
The cosine law
romanna [79]
\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-------------------------------\\\\

\bf \cfrac{sin(88^o)}{39.9}=\cfrac{sin(A)}{31}\implies \cfrac{31\cdot  sin(88^o)}{39.9}=sin(A)
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot  sin(88^o)}{39.9} \right]=sin^{-1}\left[ sin(A) \right]
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot  sin(88^o)}{39.9} \right]=\measuredangle A
\\\\\\
50.93841^o\approx \measuredangle A\qquad thus\qquad \measuredangle C\approx 41.0619^o
3 0
3 years ago
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