1.
Chance of finding a bug = 0.35
Chance of not finding a bug = 1 - 0.35 = 0.65
Probability of finding a bug in the first 3 programs =
Probability of not finding a bug in 2 out of the 3 and finding a bug in 1.:
0.65^2 * 0.35 = 0.147 = 0.15
Answer is A.
2.
Probability of heads = 0.50
Probability of tails = 0.50
Probability of heads on the fourth attempt = tails x tails x tails x heads = 0.5 x 0.5 x 0.5 x 0.5 = 0.0625
The answer is B.
Answer:

Step-by-step explanation:
we know that
Applying the <u>Intersecting Secants Theorem</u>

Solve for x




12 bags of mixed nuts for R2 each and 10 bags of dried fruit for R3 each
Excluded values are -3, 0 and 8, so denominator will be:

Answer A.