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coldgirl [10]
3 years ago
15

Work out the length of xshow working out​

Mathematics
1 answer:
Elena L [17]3 years ago
3 0

Answer:

12.12

Step-by-step explanation:

the formula to find x in this case would be:

      ______

x=√14^2-7^2

x=√c^2﹣a^2=√14^2﹣7^2≈12.12436

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Will give brainiest lol
Nat2105 [25]

Answer: 4 1/6 = 6/25

5 5/6 = 6/35

1 5/6= 6/11

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The area of a room is 600 square feet. The length is (x+2) feet and the width is (x+3) feet. Find the dimensions of the room
m_a_m_a [10]
Create an equation using the formula for area of a rectangle; area = width * length
(X + 2)(x + 3) = 600
Multiply the dimensions.
X^2 + 3x + 2x +6 = 600, or simplified x^2 +5x + 6 = 600.
Subtract 600 to get the following:
X^2 + 5x - 594 = 0
Factor by x:
(X - 22)(x + 27) = 0
Solve for x
X - 22 = 0
X = 22.
Use the POSITIVE VALUE of x as you can’t have a negative area for a room.
Then substitute 22 for x to get the dimensions
(22+ 2) or 24 for length and (22+3) or 25 for width.
6 0
3 years ago
Solve the system using elimination. ''x-3y=9 and -x+3y=-9
DiKsa [7]

Answer:

Infinitely many solutions.

Step-by-step explanation:

Let's solve your system by elimination.

x−3y=9;−x+3y=−9

x−3y=9

−x+3y=−9

Add these equations to eliminate x:

0=0

<u>Answer:</u>

Infinitely many solutions.

6 0
2 years ago
The following stem-and-leaf plot represents the scores earned by Mr. Roberts's class on their most recent science test.
Alinara [238K]
First we need to count the total number scores. This can be done from the stem and leaf plot. The total number of scores are 19. The total number of values is odd, so the median position will be:

\frac{19+1}{2}=10th

Thus the 10th score is the median score for the class of Mr. Robert. The 10th score from the stem and leaf plot is 81.

Thus 81 is the median score of Mr. Robert's Class. 
5 0
4 years ago
Read 2 more answers
What is the value of the underline digit?<br><br> 14.097
weqwewe [10]

Answer:14.097

Step-by-step explanation:

6 0
3 years ago
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