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3 years ago

Sketch the graph of y= (x-1)^2+2

Mathematics

1 answer:

yarga [219]3 years ago

7 0

That's what the graph should look like and I wrote the rest on there just incase you needed any other information.

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Please answer right away

Delicious77 [7]

Answer:

independent

Step-by-step explanation:

Since no one else answered, figured you wouldn't mind if I do. :-), and you didn't use any CAPS.

How those two events (even and greater than 9) relate?

independent: YES. Can one happen without the other? Certainly. You see (1,1) is an even number that is not greater than 9. Equally, you see (6,5) which is greater than 9, but is not an even number.

inclusive: No, since there's a least one case where a pair number is not greater than 9. The opposite is also true... at least 1 number > 9 that is not even.

Mutually exclusive: No, since there numbers that are even AND greater than 9 (6,4) for example.

Conditional: No. Does one need the other to happen? Absolutely not.

5 0

2 years ago

What is the slope for the following equation 9x + 2y = 9

MArishka [77]

Slope of the equation is -9/2

Step-by-step explanation:

Step 1: Write the equation in slope-intercept form y = mx + b

9x + 2y = 9

2y = -9x + 9

y = -9/2 x + 9/2

⇒ Slope, m = -9/2

7 0

3 years ago

What is the ratio of the diameter of any circle to its radius?<br><br> What does that mean ?

spayn [35]

The diameter fits all the way across the circle, and the radius fits half way across the circle, thus making the radius half the length of the diameter so the ratio for diameter/radius would be 2/1 or 1/.5

4 0

2 years ago

Write the slope-intercept form of the equation of the line that is perpendicular to and passes through Point X. Show all work fo

Semmy [17]

Answer:

$y =\dfrac{12}{5}x + 22$

Step-by-step explanation:

Slope-intercept form of line:

First find the slope of the line AB. ie, m

Slope of the perpendicular line = -1/m

(2 , 3) ⇒ x₁ = 2 & y₁ = 3

(-10, 8) ⇒ x₂ = -10 & y₂ = 8

$\boxed{Slope=\dfrac{y_2-y_1}{x_2-x_1}}$

$= \dfrac{8-3}{-10-2}\\\\=\dfrac{5}{-12}\\\\=\dfrac{-5}{12}$

$\sf slope \ of \ the \ perpendicular \ line \ m_1 = \dfrac{-1}{m}= -1 \ \div \dfrac{-5}{12}$

$\sf = -1 * \dfrac{12}{-5}=\dfrac{12}{5}$

Equation of the required line: y = mx + b

$y =\dfrac{12}{5}x+b$

The line passes through (-5 , 10). Substitute in the above equaiton,

$10 =\dfrac{12}{5}*(-5) + b\\\\ 10 = (-12) + b\\\\$

10 + 12 = b

b = 22

Equation of the line:

$y =\dfrac{12}{5}x + 22$

3 0

2 years ago

Write an equation of the line that passes through (1,2) and is perpendicular to the line y= 1/3x+4

zvonat [6]

Slope-intercept form: y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be perpendicular, their slopes have to be the negative reciprocal of each other. (Basically flip the sign +/- and the fraction(switch the numerator and the denominator))

For example:

Slope = 2 or $\frac{2}{1}$

Perpendicular line's slope = $-\frac{1}{2}$ (flip the sign from + to -, and flip the fraction)

Slope = $-\frac{3}{4}$

Perpendicular line's slope = $\frac{4}{3}$ (flip the sign from - to +, and flip the fraction)

y = 1/3x + 4 The slope is 1/3, so the perpendicular line's slope is $-\frac{3}{1}$ or -3.

Now that you know the slope, substitute/plug it into the equation:

y = mx + b

y = -3x + b To find b, plug in the point (1, 2) into the equation, then isolate/get the variable "b" by itself

2= -3(1) + b Add 3 on both sides to get "b" by itself

2 + 3 = -3 + 3 + b

5 = b

y = -3x + 5

5 0

2 years ago