A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
Answer:
1/18
Step-by-step explanation:
There are 36 different possible combinations. There are only two ways of rolling a sum of 11.
2/36 = 1/18
Are you asking for the expression?
If so, you plug into the format (x - h)² + (y - k)² = r² where (h, k) is the center and r is the radius.
(x + 2.5)² + (y + 4.4)² = (7/4)²
Simplify to get your equation and answer:
(x + 2.5)² + (y + 4.4)² = 49/16
Answer:
i think its a
Step-by-step explanation:
