Answer: it cost a customer $7.25 to buy five tulips and $10.5 to buy six roses.
Step-by-step explanation:
Let x represent the cost of 1 tulip.
Let y represent the cost of 1 rose.
The price of each tulip is the same and the price of each roses the same. One customer bought seven tulips and nine roses for $25.90. This means that
7x + 9y = 25.9 - - - - - - - - - - - - - - 1
Another customer bought for four tulips and eight roses for $19.80. This means that
4x + 8y = 19.8- - - - - - - - - - - - - - - 2
Multiplying equation 1 by 4 and equation 2 by 7, it becomes
28x + 36y = 103.6
28x + 56y = 138.6
Subtracting, it becomes
- 20y = - 35
y = - 35/ - 20
y = 1.75
Substituting y = 1.75 into equation 2, it becomes
4x + 8 × 1.75 = 19.8
4x + 14 = 19.8
4x = 19.8 - 14 = 5.8
x = 5.8/4
x = 1.45
The cost of 5 tulips would be
1.45 × 5 = $7.25
The cost of 6 roses would be
1.75 × 6 = $10.5
Answer:
Step-by-step explanation:
The data is not collected from the world outside, but a computer.
=> The data can be generated under assumption from simulation only.
=> Option A is correct.
Hope this helps!
:)
It’s the set of all possible outcomes
Answer: 53.13
Explanation of answer: since theta is the unknown, then you must use the inverse of sin. (Which is sin with -1 subscript) I used a calculator and used inverse of sin and put 4/5 in parenthesis
Answer: Choice C
Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.
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Explanation:
Just because the data points trend upward (as you go from left to right), it does not mean the data is linearly associated.
Consider a parabola that goes uphill, or an exponential curve that does the same. Both are nonlinear. If we have points close to or on these nonlinear curves, then we consider the scatterplot to have nonlinear association.
Also, you could have points randomly scattered about that don't fit either of those two functions, or any elementary math function your teacher has discussed so far, and yet the points could trend upward. If the points are not close to the same straight line, then we don't have linear association.
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In short, if the points all fall on the same line or close to it, then we have linear association. Otherwise, we have nonlinear association of some kind.
Joseph's claim that an increasing trend is not enough evidence to conclude the scatterplot is linear or not.
