All you have to do is divide the medium sized jerseys by the total number of jerseys and multiply by 100.
15/50*100=30%
Answer:
average atomic mass = 207.2172085 amu
Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.
For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)
The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
+ 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu
Hope this helps :)
First we need to find the length. So we do 126/3 to get 42. The length is 42. Now to find perimeter we do 2(42)+2(3) or 42+42+3+3.
Both ways are right ways. The perimeter is 90 meters.
Hope that helps!!
Amount of Interest = $36
Rate of interest = 3% per annum
Total time period for which the money was invested = 3 years
Let us assume the Principal amount = x
Then
Interest = Principal * Rate of Interest * time
36 = x * 3% * 3
36 = 9x/100
36 * 100 = 9x
3600 = 9x
x = 3600/9
= 400
So the initial sum of the money that was invested was $400.
This is a Pythagorean Theorem problem. 3^2 + 7^2 = 58. C^2 = 58. C = 7.6157 (exact)
There is no exact answer for this. The closest we can get to 58 is 7.6157, which would leave us at 57.9988. So the approximate value is 7.6, but if you need the closest answer, it’s 7.6157.
