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wariber [46]
2 years ago
13

Tisha and her academic team are working to go to state finals. They must have a certain number of points, T, to advance. They ha

ve had three local matches, b, c and d, and will attend a district match. District match points count for four times the number of points than local matches do. Choose the equation that would help Tisha find how many points they need to earn in the district match, a, to advance.

Mathematics
2 answers:
il63 [147K]2 years ago
8 0

Answer:

I think c

Step-by-step explanation:

hope this helps you

Kobotan [32]2 years ago
5 0

Answer:

i think d

Step-by-step explanation:

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Statistics show that about 42% of Americans voted in the previous national election. If three Americans are randomly selected, w
MrRa [10]

Answer:

19.51% probability that none of them voted in the last election

Step-by-step explanation:

For each American, there are only two possible outcomes. Either they voted in the previous national election, or they did not. The probability of an American voting in the previous election is independent of other Americans. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

42% of Americans voted in the previous national election.

This means that p = 0.42

Three Americans are randomly selected

This means that n = 3

What is the probability that none of them voted in the last election

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.42)^{0}.(0.58)^{3} = 0.1951

19.51% probability that none of them voted in the last election

6 0
2 years ago
Area of the figure .
blondinia [14]

Answer: the answer is not in the multiple choice.

area = 60 in^2

Step-by-step explanation:

4 0
2 years ago
NO LINKS!!!!! Write 5 summary for the data below. Show your work.
ankoles [38]

Answer:

lower \: quartile =  \frac{1}{4}  \times 8 \\  =  {2}^{nd}  \\  = 3

upper \: quatile =  \frac{3}{4}  \times 8 \\  = 6 {}^{th}  \\  = 7

median =  \frac{1}{2}  \times 8 \\  = 4 {}^{th}  \\  = 5

5 0
2 years ago
Evaluate. Write your answer as a fraction or a whole number.... what is 1/2 exponent 1
riadik2000 [5.3K]

Answer:

1/2

Step-by-step explanation:

Anything with an exponent of 1 is itself.

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B
inysia [295]

\large \bigstar \frak{ } \large\underline{\sf{Solution-}}

Consider, LHS

\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered}  \\  \\  \text{So, using this identity, we get} \\  \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered}  \\

So, using this identity, we get

\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

can be rewritten as

\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}

<h2>Hence,</h2>

\begin{gathered} \\ \rm\implies \:\boxed{\sf{  \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}

\rule{190pt}{2pt}

5 0
2 years ago
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