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atroni [7]
3 years ago
5

Find the measure of each angle indicated.

Mathematics
2 answers:
Alex3 years ago
7 0

Answer:

<em>(B). 51°</em>

Step-by-step explanation:

OLga [1]3 years ago
6 0

Answer:

51

Step-by-step explanation:

See the other answer

You might be interested in
Factor (z-5)(z+4)=52​
Ipatiy [6.2K]

Good Afternoon! Here is your answer step by step!

Let's solve your equation step-by-step.

(z−5)(z+4)=52

Step 1: Simplify both sides of the equation.

z2−z−20=52

Step 2: Subtract 52 from both sides.

z2−z−20−52=52−52

z2−z−72=0

Step 3: Factor left side of equation.

(z+8)(z−9)=0

Step 4: Set factors equal to 0.

z+8=0 or z−9=0

z=−8 or z=9

Answer:

z=−8 or z=9

Have a blessed day! ❤

4 0
3 years ago
Write the equation in standard form for the circle with center (0, -6) and radius 7.
LUCKY_DIMON [66]

Step-by-step explanation:

the equation of circle is given by

(x - h) {}^{2} + (y - k) {}^{2}  =  {r}^{2}  \\ (x - 0) {}^{2}  +  {(y + 6)}^{2}  =  {7}^{2}  \\  {x }^{2}  +  {y}^{2}  + 12y + 36 = 49 \\  {x  }^{2}  +  {y}^{2}  + 12y = 13

4 0
2 years ago
Adriana is planning to ride the public bus to and from school this year. She wants to figure out how much it will cost her. The
lutik1710 [3]

Answer:

C is the dependent variable and r is independent

Step-by-step explanation:

Adriana can ride the bus any number of times she wants. No one is stopping her from doing that so 'r' becomes an independent quantity.

Whereas, the total cost for the bus rides depends on the number of times Adriana rides the bus and the relation is given as, C=1.25r

This is because it costs $1.25 each time she rides the bus in one direction

4 0
2 years ago
3e≤6 <br><br> a e=1<br><br> b e=2<br><br> c e=3
lesya [120]
A and b are both accurate

For a:
3(1) \leqslant 6 = 3 \leqslant 6
which is true

For b:
3(2) \leqslant 6 = 6 \leqslant 6
which is also true
7 0
3 years ago
Original price: $32<br> Discount: ?<br> Sale price: $8
Sati [7]

Answer:  75%

Step-by-step explanation:

32 dollars times 75% = 24

32 - 24 = $8

6 0
3 years ago
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