Answer:
The graph with solution is shown below.
Step-by-step explanation:
We need to find the
and
for given equation.
For
, substitute 
Considering inequality sign as equality and simplifying,
, point is 
Similarly,
For
, substitute 
We get,
, point is 
We locate this two points on the graph now and join them.
The joining line will be dotted as the inequality has just 'greater than' symbol. The region above the dotted line is the solution to graph.
Answer: 266
Step-by-step explanation: This is a ratio problem. If there are 14 chocolates with nuts out of every 32 chocolates, you can use this as a ratio and set it up as a proportion.
(1) 14 chocolates w/ nuts / 32 chocolates = n chocolates / 608 chocolates
(2) Solve for n: 8,512 = 32n; n = 266
Answer:
Sorry for my bad handwriting it's hard write in a computer
Step-by-step explanation:
Answer:
150
Step-by-step explanation:
i did addition so yeah
Answer:
1.32% of students have the chance to attend the charter school.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
This year the mean on the entrance exam was an 82 with a standard deviation of 4.5.
This means that 
a.What is the percentage of students who have the chance to attend the charter school?
Students who achieve a score of 92 or greater are admitted, which means that the proportion is 1 subtracted by the pvalue of Z when X = 92. So



has a pvalue of 0.9868
1 - 0.9868 = 0.0132
0.0132*100% = 1.32%
1.32% of students have the chance to attend the charter school.