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AVprozaik [17]
2 years ago
11

Help please due today No links

Mathematics
1 answer:
GarryVolchara [31]2 years ago
4 0
See the answer in the image

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Point P' is the image of P(3,5) under a reflection across the y-axis.
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(-3,5)

Step-by-step explanation:

In reflections the x axis is the opposite only

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The coefficient of 2(3)(6)Q is ___.
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Find the sum of a finite geometric sequence from n=1 to n=8, using the expression -2(3)^n-1
MissTica
\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}
\end{cases}
\\\\\\
\sum\limits_{n=1}^{8}~-2(3)^{n-1}~~
\begin{cases}
n=8\\
a_1=-2\\
r=3
\end{cases}\implies S_8=-2\left( \cfrac{1-3^8}{1-3} \right)
\\\\\\
S_8=\underline{-2}\left( \cfrac{1-6561}{\underline{-2}} \right)\implies s_8=1-6561\implies S_8=-6560
8 0
3 years ago
MARKING BRAINLEST!!!!!!!!!
lapo4ka [179]

Answer:

A  3^4 * 3^-4 / 3^6

C 1 / 3^6

Step-by-step explanation:

( 3^2 * 3^-2)

-------------------  all the the power of 2

           3^3

First simplify the numerator

We know a^b* a^c = a^(b*c)

( 3^(2+-2))

-------------------  all to the power of 2

           3^3

( 3^(0))

-------------------  all to the power of 2

           3^3

( 3^(0))

-------------------  all to the power of 2

           3^3

We know a^b/ a^c = a^(b-c)

3^(0-3)  all to the power of 2

3^-3 all to the power of 2

3^-3 ^2

We know that a^b^c = a^(b*c)

3^(-3*2)

3^ -6

We know the negative exponent takes if from the numerator to the denominator

1 / 3^6

The other correct choice is A

3^4 * 3^-4 = 3^0 which is 1

1/3^6 is the same answer

8 0
3 years ago
Read 2 more answers
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