Answer:
A set of parametric equations for the line y = 4x - 5 is;
x = t
y = 4t - 5
Step-by-step explanation:
To find a set of parametric equations for the line y = 4x - 5;
We can assign either variable x or y equal to the parameter t, in this case we can easily let x = t
We then substitute x = t in the original equation;
y = 4t - 5
Therefore, a set of parametric equations for the line y = 4x - 5 is;
x = t
y = 4t - 5
Answer:
k < - 1
Step-by-step explanation:
28 + 3k < 5(-3-8k)
28 + 3k < - 15 - 40k
28 + 15 < - 40k - 3k
43 < - 43k
43/- 43 > k (switch signs because 43 is negative)
k < -1
So use cancelation
multiply first equation by 2
2x+8y=10
times 2
4x+16y=20
now add
4x+16y=20
<u>-4x-9y=-13 +
</u>0x+7y=7
7y=7
divide by 7
y=1
subsittue
2x+8y=10
2x+8(1)=10
2x+8=10
subtract 8 from both sides
2x=2
divide by 2
x=1
x=1
y=1
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subtract 5 from both sides to get 3y=42
divide both sides by 3 to get y = 14
