Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
I believe the answer is the first option. 1 to 3 with intervals of 1.
Hope this helps!
Answer:
994
Step-by-step explanation:
2(s+t)= 10
10^3= 1.000
1.000-6= 994
Answer: The same amount of book weighed is 14.5.
Step-by-step explanation:
So there is 5 books
9.5 pounds
9.5 + 5 = 14.5
So, Each book weighs about 14.5.
Answer:
51
Step-by-step explanation:
