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Nonamiya [84]
3 years ago
10

1/3 woodwind,1/6 percussion,1/2 brass. The Reagan School Marching Band has three percussion musicians.How many musicians altoget

her are in the band?
Mathematics
2 answers:
timofeeve [1]3 years ago
8 0
18 is the answer because... Woodwinds have 6, Percussion has 3, and Brass has 9! Hope that I helped! :)
dezoksy [38]3 years ago
4 0
18 if u change all the fractions to ?/6
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3x + 2y = 9 <br>y = 4x – 1 <br>(solve algebraically)​
postnew [5]
3x+2y=9
3x+2(4x-1)=9
11x-2=9
+2 +2
11x=11
X=1

Y=4x-1
Y=4(1)-1
Y=3
8 0
3 years ago
10. Find the theoretical probability of rolling a number less than 4 on a standard number cube
snow_lady [41]
<h3>Answer:  1/2</h3>

Explanation:

Here's the event space

E = {1,2,3}

this represents all of the desired events we want, which is rolling less than a 4 on a standard number cube (aka a die). There are A = 3 items in this set.

The sample space is the set of all possible outcomes, namely,

S = {1,2,3,4,5,6}

which is all of the values on the die. There are B = 6 items in this set.

Divide the values of A and B to get the theoretical probability:

P(rolling a number less than 4) = A/B = 3/6 = 1/2

6 0
3 years ago
Read 2 more answers
How much more area does a large pizza with a 12in. diameter have than a small pizza with a 8 in. diameter? Round your answer to
USPshnik [31]

Answer:

A is the correct answer.

Step-by-step explanation:

First do 6 times 6 and then do 36 times 3.14 to get 113.04.

Then do 4 times 4 to get 16 times 3.14 for 50.24

Last do 113 minus 50 for 63 squared.

6 0
3 years ago
A tire manufacturer wants to estimate the average number of miles that may be driven in a tire of a certain type before the tire
alexandr402 [8]

Answer:

97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

Step-by-step explanation:

We are given that a random sample of tires is chosen and are driven until they wear out and the number of thousands of miles is recorded;

32, 33, 28, 37, 29, 30, 22, 35, 23, 28, 30, 36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                                P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average number of miles = \frac{\sum X}{n} = 30.25

            s  = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} } = 4.71

            n = sample of tires = 12

            \mu = population average number of miles

<em>Here for constructing a 97% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<u>So, 97% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.55 < t_1_1 < 2.55) = 0.97  {As the critical value of t at 11 degrees of

                                              freedom are -2.55 & 2.55 with P = 1.5%}  

P(-2.55 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.55) = 0.97

P( -2.55 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.55 \times {\frac{s}{\sqrt{n} } } ) = 0.97

P( \bar X-2.55 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.55 \times {\frac{s}{\sqrt{n} } } ) = 0.97

<u>97% confidence interval for</u> \mu = [ \bar X-2.55 \times {\frac{s}{\sqrt{n} } } , \bar X+2.55 \times {\frac{s}{\sqrt{n} } } ]

                                        = [ 30.25-2.55 \times {\frac{4.71}{\sqrt{12} } } , 30.25+2.55 \times {\frac{4.71}{\sqrt{12} } } ]

                                        = [26.78 miles, 33.72 miles]

Therefore, 97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

7 0
4 years ago
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