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rosijanka [135]
3 years ago
5

Is this correct?

Mathematics
1 answer:
Kitty [74]3 years ago
4 0

i believe it is 173 and 145.

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Rewrite the Fraction 94/5 as a decimal
xenn [34]
94/5 = 18.8
since 90/5 is 18
and 4/5 is .8
just add those together
bam 
7 0
3 years ago
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Hello!
Tcecarenko [31]

This is simple algebra :)

First, we can write the question as an algebraic equation.

Given that Doug spent 40 more hours than Laura, we can represent Laura as (x) and Doug as (x+40).

"Doug and Laura spent a combined 250 hours." So we can write this as

(x) + (x+40) = 250

Now simplify:

2x + 40 = 250

Solve x by subtracting 40 from both sides of the equation:

2x = 210

Therefore:

x = 210/2

= 105

So Laura (x) spent 105 hours!

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3 years ago
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Marco draws a card and replaces it 10 times from a standard deck of 52 cards. He draws 8 red cards and 2 black cards. What is th
Andreas93 [3]
4/5 chance is the answer to that
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3 years ago
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The table shows the age of the swimmes on Dions swims team. Find the mean age of the swimmers om the team?
PilotLPTM [1.2K]
Hello!

If we want to find the mean (average) of any set of numbers, all you need to do is add the set together, then divide by how many numbers are in the set.

When we add all the numbers we get: 100

Next we just divide by the number of people which is 10: 100 divided by 10 is 10

So, the mean age of the swimmers on the team is an even number of 10.










3 0
3 years ago
I Prove that Cos(90-θ)/1+sin(90-θ) +1+sin(90-θ) /cos(90-θ) =2
USPshnik [31]
Okay,

so first you gotta know that cos(90-x) is equal to sinx and sin(90-x) is equal to cosx!!
Now all you gotta do is replace the cos(90-x) to sinx in the numerator and sin(90-x) to cosx in the denomenator inorder to make the numerator all into sin and denomenator all into cos.
After that, open up the brackets and solve...
At the end you'll hopefully get something like this :( 1+sin90 ÷ 1+cos90 )
And since sin90 is 1 (put it in the calculator!) and cos90 is 0, you'll get 2÷1 which is equals to 2!!

Hope this helped!  :)
6 0
3 years ago
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