The discontinuous at the x-value for which the denominator was zero is removable, I hope this help
Answer:
12
Step-by-step explanation:
This is assuming that x2 means x to the power of 2 and that the x on the left is to represent multiplying. First, plug in all of the number to get 2*3+3^2-3.Using PEMDAS, you should solve the exponent to get 9. Then, multiply 2 by 3 to get 6. Add 6 to 9 to get 15. Subtract 2 to 15 to get 12.
TL;DR
2*3+3^2-3
6+9-3
15-3
12
Draw an equilateral triangle with side lengths of 1. Each angle here is 60 degrees, which is true of any equilateral triangle.
Now draw another equilateral triangle that has side lengths of 2 units. Clearly this triangle is not the same size as the previous one, but the angles are all still 60 degrees.
We have an example in which there are 2 triangles with the same angles, but the triangles are not congruent. Therefore, having info about congruent angles only isn't sufficient to prove triangles to be congruent.
