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2 years ago

13

Michael deposits $875 in a savings account that pays 4.5% interest. How much money does he earn at the end of 18 months?

2 answers:

Vitek1552 [10]2 years ago

7 0

Answer: I think the answer to this question is 3,500 too

Step-by-step explanation:

Genrish500 [490]2 years ago

6 0

Answer:

I think the answer to this question is 3,500 I'm sorry if I'm wrong.

Step-by-step explanation:

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X-2/x+1 > 0, what si da solution set?

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Step-by-step explanation:

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I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

2 years ago

Find the volume of a rectanglular prism if the length is x and the width is x^2 and the height is 5x^2 +4x+1. Use the formula v=

My name is Ann [436]

Answer:

The volume = $5x^{5}+4x^{4}+x^{3}$

Step-by-step explanation:

* The rule of the volume of the rectangular prism:

- the volume of any prism = base area × height

∵ The base of the rectangular prism is rectangle

∵ Area any rectangle = Length × Width = l × w

∴ The volume of the rectangular prism = l × w × h

* In the problem:

∵ l = x , w = x² , h = 5x² + 4x + 1

∴ The volume = (x)(x²)(5x² + 4x + 1)

* We will simplify it

- Multiply x by x² and then multiply the answer by the bracket

∵ x × x² = x³

∴ x³(5x² + 4x + 1)

∵ x³ × 5x² = 5x^5

∵ x³ × 4x = 4x^4

∵ x³ × 1 = x³

∴ The volume = $5x^{5}+4x^{4}+x^{3}$

5 0

3 years ago