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3 years ago

Find an expression for the nth term (tn) in each of the following sequence:

Mathematics

1 answer:

suter [353]3 years ago

5 0

Umm do you have an attachment to it because there is no sentences

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A single die is rolled twice. The 36 equally-likely outcomes are shown to the right. Find the probability of getting first an o

dangina [55]

36 equally-likely outcome: (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1),(6,2), (6,3), (6,4), (6,5), (6,6)

Solution:
Outcomes with first number being old number and second being even number: (1,2), (1,4), (1,6), (3,2), (3,4), (3,6), (5,2), (5,4), (5,6) = 9 outcomes

P(old,even) = 9/36 =1/4 = 0.25

5 0

3 years ago

Read 2 more answers

Which of the triangles are right triangles ? 1 2 3 4

alexdok [17]

Answer:

Your best answer would be number 4

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

What are two numbers whose sum is 11 and whose product is -60?

scoray [572]

Step 1:
Enumerate pairs of numbers whose product is 60
(1,60)
(2,30)
(3,20)
(4,15)
(5,12)
(6,10)
(10,6)
...
2. identify the pair whose components have a difference of 11.
(4,15)
3. attach a negative sign to the smaller component so that the sum is +11.
(-4,15)

Answer: the numbers are -4 and 15.

4 0

4 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago

Susie is paying $540.15 every month for her $150,000 mortgage. If this is a 30 year mortgage, how much interest will she pay ove

GuDViN [60]

Answer:

17310.6

$540.15 multiply 30

because if they ask all in every month is 540.15

and she got 30 year

6 0

3 years ago